The reaction of `C_(2)H_(5)OH` with `H_(2)SO_(4)` does not give

Options

A. Ethylene
B. Diethyl ether
C. Acetylene
D. Ethyl hydrogen sulphate

Explanation

To solve the question regarding the reaction of ethanol (C2H5OH) with sulfuric acid (H2SO4), we need to analyze the possible products formed during the reaction.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are ethanol (C2H5OH) and concentrated sulfuric acid (H2SO4).

2. **Protonation of Ethanol**:
- When ethanol reacts with concentrated sulfuric acid, the hydroxyl group (-OH) of ethanol gets protonated. This forms a better leaving group, resulting in the formation of an oxonium ion (C2H5OH2+).

3. **Formation of Carbocation**:
- The protonated ethanol can lose a water molecule (H2O), leading to the formation of a carbocation (C2H5+). This is a key intermediate in the reaction.

4. **Possible Elimination Reactions**:
- The carbocation (C2H5+) can undergo elimination reactions. If a β-hydrogen is removed, it can lead to the formation of ethylene (C2H4) through a dehydration process.

5. **Other Possible Products**:
- The carbocation can also react with another molecule of ethanol, leading to the formation of diethyl ether (C2H5OC2H5) through a nucleophilic attack.
- Additionally, the carbocation can react with the bisulfate ion (HSO4-) from sulfuric acid to form ethyl hydrogen sulfate (C2H5OSO3H).

6. **Identify the Product that Cannot Form**:
- Among the possible products, we need to identify which one cannot be formed. The options include:
- Ethylene (C2H4)
- Diethyl ether (C2H5OC2H5)
- Ethyl hydrogen sulfate (C2H5OSO3H)
- Acetylene (C2H2)

- Acetylene (C2H2) cannot be formed from the reaction of ethanol with sulfuric acid, as it requires a different reaction pathway that involves dehydrohalogenation or other specific conditions.

### Conclusion:
The reaction of C2H5OH with H2SO4 does not give acetylene (C2H2).