Ethylene gylcol gives oxalic acid on oxidation with

Options

A. Acidified `K_(2)Cr_(2)O_(7)`
B. Acidified `KMnO_(4)`
C. Alkaline `KMnO_(4)`
D. Periodic acid

Explanation

To determine the oxidizing agent that converts ethylene glycol into oxalic acid, we can follow these steps:

### Step 1: Identify the structure of ethylene glycol
Ethylene glycol, also known as ethane-1,2-diol, has the chemical formula C2H6O2. Its structure consists of two hydroxyl (-OH) groups attached to a two-carbon chain.

### Step 2: Understand the oxidation process
Oxidation involves the loss of electrons or an increase in oxidation state. In the case of ethylene glycol, the hydroxyl groups can be oxidized to form carbonyl groups, which can further oxidize to carboxylic acids.

### Step 3: Recognize the product of oxidation
When ethylene glycol is oxidized, it can form oxalic acid (C2H2O4). Oxalic acid contains two carboxylic acid groups (-COOH) and is the simplest dicarboxylic acid.

### Step 4: Identify suitable oxidizing agents
Common oxidizing agents that can oxidize alcohols to carboxylic acids include:
- Acidified potassium dichromate (K2Cr2O7)
- Periodic acid (HIO4)

### Step 5: Conclusion
Among the oxidizing agents mentioned, acidified potassium dichromate (K2Cr2O7) is a well-known strong oxidizing agent that can effectively oxidize ethylene glycol to oxalic acid.

### Final Answer
Ethylene glycol gives oxalic acid on oxidation with **acidified potassium dichromate (K2Cr2O7)**.

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