Three elements Na, S and O combine to form a compound `Na_(2)SO_(3)` what is the valency of S in this compound ?

Options

A. 2+
B. 4+
C. 6+
D. 8+

Explanation

To determine the valency of sulfur in the compound \( \text{Na}_2\text{SO}_3 \), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Compound**: The compound given is \( \text{Na}_2\text{SO}_3 \).

2. **Know the Oxidation States**:
- Sodium (Na) typically has an oxidation state of \( +1 \).
- Oxygen (O) typically has an oxidation state of \( -2 \).

3. **Set Up the Equation**:
- In the compound \( \text{Na}_2\text{SO}_3 \), there are 2 sodium atoms, 1 sulfur atom, and 3 oxygen atoms.
- The total oxidation states can be expressed as:
\[ 2 \times (+1) + x + 3 \times (-2) = 0 \]
- Here, \( x \) represents the oxidation state of sulfur (S).

4. **Calculate the Total**:
- Substitute the values into the equation:
\[ 2 + x - 6 = 0 \]

5. **Solve for \( x \)**:
- Rearranging the equation gives:
\[ x - 4 = 0 \]
- Thus, \( x = +4 \).

6. **Conclusion**: The oxidation state of sulfur in \( \text{Na}_2\text{SO}_3 \) is \( +4 \), which means the valency of sulfur is also \( 4 \).

### Final Answer:
The valency of sulfur (S) in the compound \( \text{Na}_2\text{SO}_3 \) is \( 4 \).

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