A card is drawn at random from a well shuffled pack of 52 cards. Find the probability that the card drawn is neither a red card nor a queen.

Explanation

To find the probability that a card drawn from a well-shuffled pack of 52 cards is neither a red card nor a queen, we can follow these steps:

### Step-by-Step Solution

1. **Identify the Total Number of Cards**:
A standard deck of cards has 52 cards.

2. **Identify the Red Cards**:
In a deck, there are 26 red cards (13 hearts and 13 diamonds).

3. **Identify the Queens**:
There are 4 queens in total (1 from each suit: hearts, diamonds, clubs, and spades).

4. **Identify the Red Queens**:
Among the 4 queens, 2 are red (the queen of hearts and the queen of diamonds).

5. **Calculate the Total Number of Cards that are Red or Queens**:
- Total red cards = 26
- Total queens = 4
- Red queens (which are already counted in the red cards) = 2
- Therefore, the total number of cards that are either red or queens = Total red cards + Total queens - Red queens
= 26 + 4 - 2 = 28

6. **Calculate the Number of Cards that are Neither Red Nor Queens**:
- Total cards = 52
- Cards that are red or queens = 28
- Therefore, the number of cards that are neither red nor queens = Total cards - Cards that are red or queens
= 52 - 28 = 24

7. **Calculate the Probability**:
The probability of drawing a card that is neither red nor a queen is given by the formula:
\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \]
Thus,
\[ \text{Probability} = \frac{24}{52} \]

8. **Simplify the Probability**:
To simplify \(\frac{24}{52}\), we can divide both the numerator and denominator by 4:
\[ \frac{24 \div 4}{52 \div 4} = \frac{6}{13} \]

### Final Answer:
The probability that the card drawn is neither a red card nor a queen is \(\frac{6}{13}\).