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The number of points with integral coord...

The number of points with integral coordinates that lie in the interior of the region common to the circle `x^(2)+y^(2)=16` and the parabola `y^(2)=4x`, is

A

8

B

10

C

16

D

none of these

Text Solution

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The correct Answer is:
To find the number of integral coordinate points that lie in the interior of the region common to the circle \(x^2 + y^2 = 16\) and the parabola \(y^2 = 4x\), we will follow these steps: ### Step 1: Understand the equations 1. The equation of the circle is \(x^2 + y^2 = 16\), which has a center at \((0,0)\) and a radius of \(4\). 2. The equation of the parabola is \(y^2 = 4x\), which opens to the right. ### Step 2: Determine the boundaries - For the circle, the interior condition is given by: \[ x^2 + y^2 < 16 \] - For the parabola, the interior condition is given by: \[ y^2 < 4x \] ### Step 3: Analyze the range of \(x\) - The circle restricts \(x\) to the interval \([-4, 4]\). - The parabola \(y^2 = 4x\) is only defined for \(x \geq 0\), so we further restrict \(x\) to the interval \([0, 4]\). ### Step 4: Check integer values of \(x\) - The possible integer values for \(x\) in the interval \([0, 4]\) are \(0, 1, 2, 3, 4\). ### Step 5: Determine corresponding \(y\) values for each \(x\) 1. **For \(x = 0\)**: - From the circle: \(0^2 + y^2 < 16 \Rightarrow y^2 < 16 \Rightarrow -4 < y < 4\) (possible \(y\) values: \(-3, -2, -1, 0, 1, 2, 3\) → 7 values) - From the parabola: \(y^2 < 4 \cdot 0 \Rightarrow y^2 < 0\) (no valid \(y\) values) - **Total points: 0** 2. **For \(x = 1\)**: - From the circle: \(1^2 + y^2 < 16 \Rightarrow y^2 < 15 \Rightarrow -\sqrt{15} < y < \sqrt{15}\) (possible \(y\) values: \(-3, -2, -1, 0, 1, 2, 3\) → 7 values) - From the parabola: \(y^2 < 4 \cdot 1 \Rightarrow y^2 < 4 \Rightarrow -2 < y < 2\) (possible \(y\) values: \(-1, 0, 1\) → 3 values) - **Total points: 3** 3. **For \(x = 2\)**: - From the circle: \(2^2 + y^2 < 16 \Rightarrow y^2 < 12 \Rightarrow -\sqrt{12} < y < \sqrt{12}\) (possible \(y\) values: \(-3, -2, -1, 0, 1, 2, 3\) → 7 values) - From the parabola: \(y^2 < 4 \cdot 2 \Rightarrow y^2 < 8 \Rightarrow -\sqrt{8} < y < \sqrt{8}\) (possible \(y\) values: \(-2, -1, 0, 1, 2\) → 5 values) - **Total points: 5** 4. **For \(x = 3\)**: - From the circle: \(3^2 + y^2 < 16 \Rightarrow y^2 < 7 \Rightarrow -\sqrt{7} < y < \sqrt{7}\) (possible \(y\) values: \(-2, -1, 0, 1, 2\) → 5 values) - From the parabola: \(y^2 < 4 \cdot 3 \Rightarrow y^2 < 12 \Rightarrow -\sqrt{12} < y < \sqrt{12}\) (possible \(y\) values: \(-3, -2, -1, 0, 1, 2, 3\) → 7 values) - **Total points: 5** 5. **For \(x = 4\)**: - From the circle: \(4^2 + y^2 < 16 \Rightarrow y^2 < 0\) (no valid \(y\) values) - From the parabola: \(y^2 < 4 \cdot 4 \Rightarrow y^2 < 16 \Rightarrow -4 < y < 4\) (possible \(y\) values: \(-3, -2, -1, 0, 1, 2, 3\) → 7 values) - **Total points: 0** ### Step 6: Sum the total points - Total points from all valid \(x\) values: - \(0 + 3 + 5 + 5 + 0 = 13\) ### Final Answer The total number of points with integral coordinates that lie in the interior of the common region is **13**.

To find the number of integral coordinate points that lie in the interior of the region common to the circle \(x^2 + y^2 = 16\) and the parabola \(y^2 = 4x\), we will follow these steps: ### Step 1: Understand the equations 1. The equation of the circle is \(x^2 + y^2 = 16\), which has a center at \((0,0)\) and a radius of \(4\). 2. The equation of the parabola is \(y^2 = 4x\), which opens to the right. ### Step 2: Determine the boundaries - For the circle, the interior condition is given by: ...
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