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If x^2+9y^2+25z^2=xyz(15/x+5/y+3/z) then...

If `x^2+9y^2+25z^2=xyz(15/x+5/y+3/z)` then x,y,z in

A

A.P.

B

G.P.

C

A.G.P.

D

H.P.

Text Solution

Verified by Experts

The correct Answer is:
D

We have,
`x^(2)+9y^(2)+25z^(2)=xyz((15)/(x)+(5)/(y)+(3)/(z))`
`rArr" "x^(2)+9y^(2)+25z^(2)-15yz-5xz-3xy=0`
`rArr" "(x^(2)-6xy+9y^(2))+(9y^(2)+25z^(2)-30yz)+(x^(2)-10xz+25z^(2))=0`
`rArr" "(x-3y)^(2)+(3y-5z)^(2)+(x-5z)^(2)=0`
`rArr" "x-3y=0,3y-5z=andx-5z=0`
`rArr" "x=3y=5z`
`rArr" "(x)/(1)=(y)/(1//3)=(z)/(1//5)=(1)/(lamda)" (say)"rArrx=(1)/(lamda),y=(1)/(3lamda),z=(1)/(5lamda)`
Clearly, x,y,z are in H.P.
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