The value of 16^("log"(4)3), is...

The value of `16^("log"_(4)3)`, is

A

8

B

3

C

4

D

9

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The correct Answer is:

D

We have,
`16^("log"4^(3)) = 4^(2"log" 4 )""^(3) = 4^("log"4)""^(3^(2)) = 3^(2) = 9`

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