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The differential equation (dy)/(dx)+P y=...

The differential equation `(dy)/(dx)+P y=Q y^n ,\ n >2` can be reduced to linear form y substituting `z=y^(n-1)` b. `z=y^n` c. `z=y^(n+1)` d. `z=y^(1-n)`

A

`z=y^(n-1)`

B

`z=y^(n)`

C

`z=y^(n+1)`

D

`z=y^(1-n)`

Text Solution

Verified by Experts

The correct Answer is:
D
We have, `(1)/(y^(n))(dy)/(dx)+P(1)/(y^(n-1))=Q`
It reduces to linear form by substituting `(1)/(y^(n-1))=z`
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