How would you determine the standard red...

How would you determine the standard reduction potential of the system `Mg^(2+)|Mg`?

Text Solution

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The standard electrode potential of `Mg^(2+)|Mg` system can be measured by connecting the Mg electrode immersed in 1M `Mg^(2+)` solution with S.H.E. This may be represented as :
`Mg|Mg^(2+) (1M) ||H^(+) ( 1M) |H_2` 1 atm , Pt
From measured potential `E_((Mg^(2+) |Mg))^(Theta)` can be calculated
`E_(cell)^(@) = E_((H^(+)|H_(2))^(Theta) - E_((Mg^(2+)|Mg))^(Theta)`
`therefore E_((Mg^(2+)|Mg))^(Theta) = 0 - E_(cell)^(@)`
This is similar to the method discussed for `Zn^(2+)|Zn` system .

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Standard reduction potential is calculated at

`27^(@)C`

`25^(@)C`

`0^(@)C`

`100^(@)C`

Standard reduction potential of an element equal to

`+ 1 xx` its reduction potential

`- 1 xx ` its standard oxidation potential

`0.00`V

`+ 1 xx ` its standard oxidation potential

The first ionization potential of Mg is

less than Al

more than Al

equal to Al

can be less or more than Al