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Number of hydrogen ions present in 10 mi...

Number of hydrogen ions present in 10 millionth part of 1.33 cm of pure water at 25°C is

A

6.023 million

B

60 million

C

8.01 million

D

80.23 million.

Text Solution

Verified by Experts

The correct Answer is:
C
Now, `[H^(+)] = 10^(-7) mol//L`
Now, 1000 mL contains `10^(-7)` mole `H^(+)` ions
1 mL contains `10^(-7)/1000` mole `H^(+)`
`1.33 xx 10^(-7)` mL contains `1.33 xx 10^(-17)` mole `H^(+)` 10 million `=10^(-7)`
so, 10 million th part of 1.33 `cm^(3) = 1.33 xx 10^(-7)` mL
So, no. of `H^(+)` ions `=1.33 xx 10^(-17) xx N_(A)`
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Knowledge Check

  • Number of hydrogen ions present in 10 millionth part of 1.33 cm^(3) of pure water at 25^(@)C is

    A
    6.023 million
    B
    60 million
    C
    8.01 million
    D
    80.23 million

  • The number of hydrogen ions in 10 ml of a solution with pH=13 is

    A
    `10^(13)`
    B
    `6.023 xx 10^8`
    C
    `6.023 xx 10^(10)`
    D
    `6.023 xx 10^(13)`

  • Number of H^(+) ions present in 10 mL of solution of pH=3 are:

    A
    `10^(13)`
    B
    `6.02xx10^(18)`
    C
    `6.02xx10^(13)`
    D
    `6.002xx10^(10)`

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    The number of molecules present in 1 cm^(3) of water is :-

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