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The time taken for an electron to comple...

The time taken for an electron to complete one revolution in Bohr orbit of hydrogen atom is

A

`(4m^(2)pir^(2))/(n^(2)h^(2))`

B

`(n^(2)h^(2))/(4mr^(2))`

C

`(4pi^(2)mr^(2))/(nh)`

D

`(nh)/(4pi^(2)mr^(2))`

Text Solution

Verified by Experts

We know according to Bohr.s theory `mvr=(nh)/(2pi)`
`rArrv=(nh)/(2pimr)`
`therefore` Time required for one complete revolution,
`T=(2pir)/v=(2pir)/(nh)2pimr=(4pi^(2)mr^(2))/(nh)`
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