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The time taken for an electron to comple...

The time taken for an electron to complete one revolution in Bohr orbit of hydrogen atom is

A

`(4m^(2)pir^(2))/(n^(2)h^(2))`

B

`(n^(2)h^(2))/(4mr^(2))`

C

`(4pi^(2)mr^(2))/(nh)`

D

`(nh)/(4pi^(2)mr^(2))`

Text Solution

Verified by Experts

We know according to Bohr.s theory `mvr=(nh)/(2pi)`
`rArrv=(nh)/(2pimr)`
`therefore` Time required for one complete revolution,
`T=(2pir)/v=(2pir)/(nh)2pimr=(4pi^(2)mr^(2))/(nh)`
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Knowledge Check

  • Time taken for an electron to complete one revolution in the Bohr orbit of hydrogen atom is

    A
    `(4pi^(2) mr^(2))/(nh)`
    B
    `(nh)/(4pi^(2)mr)`
    C
    `(2pimr)/(n^(2) h^(2))`
    D
    `(h)/(2pi mr)`

  • Time taken for an electron to complete one revolution in the Bohr orbit of hydrogen atom is

    A
    `(nh)/(4pi^(2)mr)`
    B
    `(4pi^(2)mr^(2))/(nh)`
    C
    `(2pimr)/(n^(2)h^(2))`
    D
    `h/(2pimr)`

  • Time taken by an electrons to complete one revolution in the Bohr orbit of the H atom is

    A
    `(4pi^(2)mr^(2))/(hm)`
    B
    `(nh)/(4pi^(2)mr)`
    C
    `(2pimr)/(n^(2)h^(2))`
    D
    `(h)/(2pimr)`

    • Similar Questions

    Explore conceptually related problems

    The time taken by the electron in one complete revolution in the n^(th) Bohr's orbit of the hydrogen atom is :

    The energy of an electron in the nth Bohr orbit of hydrogen atom is

    The radius of second Bohr’s orbit of Hydrogen atom is:

    According to Bohr's theory, the ratio of the times taken by the electron in a hydrogen atom to complete one revolution in orbits corresponding to ground and first excited states is

    The energy of an electron in second Bohr orbit of hydrogen atom is :

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