Home
Class 12
CHEMISTRY
0.126 g of an acid is needed to complete...

0.126 g of an acid is needed to completely neutralise 20 mL 0.1 N NaOH solution. The equivalent weight of the acid is

A

53

B

40

C

45

D

63

Text Solution

Verified by Experts

The correct Answer is:
D
Equivalents of acid = Equivalents of base
`=(NV)/1000 =(0.1 xx 20)/1000 = 2 xx 10^(-3)`
No. of gram equivalents `=("mass")/("Equivalent mass")`
`2 xx 10^(-3) = 0.126/("Equivalent mass")`
Equivalent mass `=0.126/(2 xx 10^(-3)) = 126/2 = 63`
Promotional Banner

Topper's Solved these Questions

  • ATOMS MOLECULES AND CHEMICAL ARITHEMETIC

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS (CATEGORY 2: SINGLE OPTION CORRECT TYPE (2 MARKS))|3 Videos

  • ATOMS MOLECULES AND CHEMICAL ARITHEMETIC

    MTG-WBJEE|Exercise WB JEE WORKOUT (CATEGORY 3: ONE OR MORE THAN ONE OPTION CORRECT TYPE (2 MARKS))|10 Videos

  • ATOMIC STRUCTURE

    MTG-WBJEE|Exercise WB JEE Previous Years Questions (CATEGORY 2 : Single Option Correct Type (2 Marks)|1 Videos

  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    MTG-WBJEE|Exercise WB JEE Previous Years Questons (Category 2 : One or More than one Option Correct Type )|3 Videos

Similar Questions

Explore conceptually related problems

0.1914 g of an organic acidi s dissolved in about 20 ml of water. 25 ml of 0.12 N NaOH is required for the complete neutralizatioonf the acid solution. The equivalent weight of the acid is

0.1914 g of an organic acid is dissolved in about 20 mL of water. 25 mL of 0.12 N NaOH is required for complete neutralization of the acid solution. The equivalent mass of the acid is

0.45 g of a dibasic acid is completely netralised with 100 ml N/10 NaOH . The molecular weight of acid is

0.14 gm of an acid required 12.5 ml of 0.1 N NaOH for complete neuturalisation.The equivalent mass of the acid is:

A solution containing 3.00 g of a monobasic organic acid was just neutralised by 40 mL of 05 N NaOH solution. Calculate the molecular weight of the acid.