In an examination it is required to get 65% of the aggregate marks to paass, A student gets 847 marks and is declared failed by 10% marks. What are the maximum aggregate marks a student can get ?

Options

A. 1450
B. 1640
C. 1500
D. None of these

Explanation

To solve the problem step by step, we will follow the reasoning provided in the video transcript.

### Step 1: Understand the problem
We know that a student needs to score 65% of the maximum aggregate marks to pass the examination. The student scored 847 marks but failed by 10% of the required passing marks.

### Step 2: Determine the effective passing percentage
Since the student failed by 10% of the passing marks, we can calculate the effective percentage the student achieved. The passing percentage is 65%, and failing by 10% means the student effectively scored 65% - 10% = 55% of the maximum aggregate marks.

### Step 3: Set up the equation
Let the maximum aggregate marks be represented by \( x \). According to the problem, the student scored 55% of \( x \), which is equal to 847 marks. We can express this mathematically as:
\[ \frac{55}{100} \times x = 847 \]

### Step 4: Solve for \( x \)
To find \( x \), we can rearrange the equation:
\[ x = \frac{847 \times 100}{55} \]

### Step 5: Calculate \( x \)
Now, we will perform the calculation:
\[ x = \frac{84700}{55} \]
Calculating this gives:
\[ x = 1540 \]

### Conclusion
The maximum aggregate marks a student can get is **1540**.