An electron and a photon each have a wavelength 1.00 nm. Find
(i) their momenta,
(ii) the energy of the photon and
(iii) the kinetic energy of electron.

Explanation

(i) Monenty `p=h/lambda=(6.63xx10^(-34))/(10^(-9))=6.63xx10^(-25)kgms^(-1)`.
(ii) Energy `p=(hc)/lambda=((6.63xx10^(-34))xx(3xx10^(8)))/(10^(-9)xx(1.6xx10^(-19)))=1243eV.`
(iii) Kinetic Energy `E_k=1/2p^2/m=1/2((6.63xx10^(-25))^2)/(9xx10^(-31)xx(1.6xx10^(-19)))=1.52eV`.