Home
Class 12
PHYSICS
The work function (phi0), of a metal X, ...

The work function `(phi_0)`, of a metal X, equals `3xx10^(-19)J`. Calculate the number (N) of photons, of light of wavelength 26.52nm, whose total energy equal W. Plank's constant `=6.63xx10^(-34)Js.`

Text Solution

Verified by Experts

`W=nhv=nh//lamda`
`3xx10^(-19)=(n.6.63xx10^(34)xx3xx10^(8))/(26.52xx10^(-9))`
`n=(3xx10^(-19)xx26.52xx10^(-9))/(6.63xx10^(-34)xx3xx10^(8))`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • XII BOARDS

    XII BOARDS PREVIOUS YEAR|Exercise SECTIONS-C|13 Videos
  • XII BOARDS

    XII BOARDS PREVIOUS YEAR|Exercise SECTIONS-D|4 Videos
  • XII BOARDS

    XII BOARDS PREVIOUS YEAR|Exercise C.B.S.E.CLASS-XII PHYSICS (THEORY) [SET-I] (SECTION-A)|5 Videos
  • SAMPLE PAPER 2019

    XII BOARDS PREVIOUS YEAR|Exercise SECTION D|6 Videos

Similar Questions

Explore conceptually related problems

The momentum of a photon of de Broglie wavelength 5000Å is …………… . [Plank's constant =6.63xx10^(-34)J.s ]

If the total energy of radiation of frequency 10^(14)Hz is 6.63J , calculate the number of photons in the radiation. (Planck's constant =6.63xx10^(-34)J-s ).

Knowledge Check

  • A Photon of red light having wavelength 600 nm has energy equal of (h=6.6xx10^(-34)Js) :

    A
    `3.3xx10^(-19)J`
    B
    `1.0xx10^(-19)J`
    C
    `3.0xx10^(-18)J`
    D
    `1xx10^(19)J`
  • Calculate the energy in joule corresponding to light of wavelength 45 nm (Planck.s constant h=6.63xx10^(-34) Js, speed of light c=3xx10^(8) ms^(-2))

    A
    `6.67xx10^(12)`
    B
    `4.42xx10^(-13)`
    C
    `4.42xx10^(-18)`
    D
    `6.67xx10^(12)`
  • Calculate the energy in joule corresponding to light of wavelength 45 nm (Planck.s constant h=6.63xx10^(-34) Js, speed of light c=3xx10^(8) ms^(-2))

    A
    `6.67xx10^(12)`
    B
    `4.42xx10^(-13)`
    C
    `4.42xx10^(-18)`
    D
    `6.67xx10^(12)`
  • Similar Questions

    Explore conceptually related problems

    Calculate the energy in eV for each photon for light of wavelength 4950Å . Take h=6.6xx10^(-34)J-s

    The work function of sodium metal is 4.41xx10^(-19)J . If photons of wavelength 300 nm are incident on the metal, the kinetic energy of the ejected electrons will be (h=6.63xx10^(34)Js,c=3xx10^(8) m/s ______ xx10^(-21)

    Calculate the energy in joule corresponding to light of wavelength 45 nm (Planck's constant, h = 6.63 xx 10^(-34) Js, speed of light = 3 xx 10^(8) ms^(-1) )

    Calculate the energy in joule corresponding to light of wavelength 45 nm : (Planck' constant h = 6.63 xx 10^-34 Js , speed of light c = 3 xx 10^8 ms^-1 )

    The energy of a photon wavelength k = 1 meter is (Planck's constant = 6.625 xx 10^(-34) Js, speed of light = 3 xx 10^(8) m//s )