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Find the angle between two vectors vec...

Find the angle between two vectors ` vec a`and ` vec b`with magnitudes `sqrt(3)`and 2 respectively having ` vec a. vec b=sqrt(6)`

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To find the angle between two vectors \( \vec{a} \) and \( \vec{b} \) with given magnitudes and dot product, we can follow these steps: ### Step 1: Write down the formula for the dot product The dot product of two vectors \( \vec{a} \) and \( \vec{b} \) can be expressed as: \[ \vec{a} \cdot \vec{b} = |\vec{a}| |\vec{b}| \cos \theta \] where \( |\vec{a}| \) and \( |\vec{b}| \) are the magnitudes of the vectors, and \( \theta \) is the angle between them. ...
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Find the angle between two vectors vec aa n d vec b with magnitudes sqrt(3) and 2 respectively and such that vec adot vec b=sqrt(6.)

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Knowledge Check

  • The angle between two vectors vec(a) and vec(b) with magnitudes sqrt(3) and 4, respectively and vec(a). vec(b) = 2 sqrt(3) is: a) 2π/3 b) π/2 c) π/3 d) π/6

    A
    `(2pi )/( 3)`
    B
    `( pi )/(2)`
    C
    `( pi )/( 3)`
    D
    `( pi )/( 6)`
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