Home
Class 11
PHYSICS
The acceleration due to gravity is g at ...

The acceleration due to gravity is `g` at a point distant `r` from the centre of earth of radius `R`. If `r lt R`, then

A

`g prop r`

B

`g prop r^2`

C

`g prop r^(-1)`

D

`g prop r^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A

`g prop r`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • GRAVITATION

    MTG GUIDE|Exercise NEET CAFE TOPICWISE PRACTICE QUESTIONS (GRAVITATIONAL POTENTIAL ENERGY AND GRAVITATIONAL POTENTIAL)|6 Videos
  • GRAVITATION

    MTG GUIDE|Exercise NEET CAFE TOPICWISE PRACTICE QUESTIONS (ESCAPE VELOCITY)|51 Videos
  • GRAVITATION

    MTG GUIDE|Exercise NEET CAFE TOPICWISE PRACTICE QUESTIONS (UNIVERSAL LAW OF GRAVITATION)|15 Videos
  • BEHAVIOUR OF PERFECT GAS AND KINETIC THEORY

    MTG GUIDE|Exercise AIPMT / NEET (MCQs)|11 Videos
  • KINEMATICS

    MTG GUIDE|Exercise AIPMT/ NEET MCQs|31 Videos

Similar Questions

Explore conceptually related problems

The dependence of acceleration due to gravity g on the distance r from the centre of the earth, assumed to be sphere of radius R of uniform density is a shown in figures along side. The correct figure is

The acceleration due to gravity at a depth R//2 below the surface of the earth is

Knowledge Check

  • If g denotes the value of acceleration due to gravity at a point distance r from the centre of earth of radius R . If r lt R , then

    A
    `g prop r^(2)`
    B
    `g prop r`
    C
    `g prop 1//r^(2)`
    D
    `g prop 1//r`
  • The dependence of acceleration due to gravity g on the distance r from the centre of the earth, assumed to br a sphere of radius R of uniform density is as shoen in Fig. below: The correct figure is

    A
    `(4)`
    B
    `(1)`
    C
    `(2)`
    D
    `(3)`
  • If R= radius of the earth and g= acceleration due to gravity on the surface of the earth, the acceleration due to gravity at a distance (r lt R) from the centre of the earth is proportional to

    A
    `r`
    B
    `r^(2)`
    C
    `r^(-2)`
    D
    `r^(-1)`
  • Similar Questions

    Explore conceptually related problems

    The value of the acceleration due to gravity is g1 at a height h=(R)/(2)(R= radius of the earth) from the surface of the earth.It is again equal to (g1/2) at a depth d below the surface of the earth.The ratio d/R equals:

    If R= radius of the earth and g= acceleration due to gravity on the surface of the earth, the acceleration due to gravity at a distance (r gt R) from the centre of the earth is proportional to

    The acceleration due to gravity at an interior point of the Earth, at a distance r from the centre of the Earth, varies as

    Variation of acceleration due to gravity (g) with distance x from the centre of the Earth is best represented by (R to Radius of the Earth)

    If acceleration due to gravity at distance d [ < R ] from the centre of earth is beta , then its value at distance d above the surface of earth will be [ where R is radius of earth ]