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The escape velocity for a body projected...

The escape velocity for a body projected vertically upwards from the surface of earth is 11km/s. If the body is projected at an angle of `45^@` with the vertical, the escape velocity will be

A

`11 // sqrt2 km//sec `

B

`11 sqrt2 km//sec `

C

`2km//sec `

D

`11 km //sec `

Text Solution

Verified by Experts

The correct Answer is:
D
`v_e = sqrt((2GM)/(R ))`
Since the escape velocity is independent of direction of projection, therefore escape velocity of the body, projected at an angle of `45^@` with the vertical will be same, i.e., 11 km/sec.
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