In the adjoining figure, ABCD is a rectangle whose diagonals AC and BD intersect at O. If `angle OAB =28^(@), " find " angle OBC.`
Text Solution
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We know that the diagonals of a rectangle are equal and bisect each other. `therefore OA =OB rArr angle OBA = angle OAB =28^(@)`. Also, each angle of a rectangle measures `90^(@)`. `therefore angle ABC =90^(@) rArr angle OBA + angle OBC =90^(@)` `therefore 28^(@)+angle OBC =90^(@) rArr angle OBA =(90^(@)-28^(@))=62^(@).`
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