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A boat goes 16 km upstream and 24 km dow...

A boat goes 16 km upstream and 24 km downstream in 6 hrs. Also it covers 12 km upstream and 36 km downstream in the same time. Find the speed of the boat upstream and downstream

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Let the speed of the boat in still water be x km/hr and the speed of the stream be y km/hr. Then,
speed upstream = ` (x - y )` km/hr
and speed downstream = = ` (x + y ) `km /hr.
Time taken to cover 16 km upstream = `(16)/((x- y)) `hours .
Time taken to cover 24 km downstream = ` ( 24 )/(( x+ y ))` hours
Total time taken = 6 hours.
` therefore (16)/(x -y ) + ( 24)/( x + y ) = 6 " " `... (i)
Again, time taken to cover 12 km upstream = `( 12)/(( x - y ))` hours.
Time taken to cover to 36 km downstream = ` ( 36)/(( x + y )) `hours.
Total time taken = 6hours.
` therefore ( 12)/(x- y ) + ( 36)/( x+ y ) = 6 " " `... (ii)
Putting ` ( 1)/((x - y )) = u and (1)/((x + y )) = v ` in (i) and (ii), we get
` 16 u+ 24v = 6 rArr 8 u + 12 v = 3," " ` ... (iii)
`12 u + 36 v = 6 rArr 2u + 6v = 1 " " `... (iv)
On multiplying (iv) by 4 and subtracting (iii) from the result, we get
` 12 v = 1 rArr v = (1)/(12)`
` rArr (1)/(x + y ) = (1)/(12) rArr x + y = 12 " "` ... (v)
On multiplying (iv) by 2 and subtracting the result from (iii), we get
` 4u = 1 rArr u = (1)/(4) `
` rArr (1)/(x - y ) = (1)/(4) rArr x - y =4. " " `... (vi)
On adding (v) and (vi), we get ` 2x = 16 rArr x = 8`
On subtracting (vi) from (v), we get `2y = 8 rArr y = 4 `.
` therefore ` speed of the boat in still water = 8 km/hr ,
and speed of the stream = 4 km/hr.
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