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When origin is shifted to the point (4, ...

When origin is shifted to the point (4, 5) without changing the direction of the coordinate axes, the equation `x^(2)+y^(2)-8x-10y+5=0` is tranformed to the equation `x^(2)+y^(2)=K^(2)`. Value of `|K|` is

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To solve the problem, we need to transform the given equation when the origin is shifted to the point (4, 5). The original equation is: \[ x^2 + y^2 - 8x - 10y + 5 = 0 \] ### Step 1: Shift the Origin When the origin is shifted to the point (4, 5), we need to express the new coordinates in terms of the old coordinates. Let: - \( X = x - 4 \) - \( Y = y - 5 \) ### Step 2: Substitute the New Coordinates We will substitute \( x = X + 4 \) and \( y = Y + 5 \) into the original equation: \[ (X + 4)^2 + (Y + 5)^2 - 8(X + 4) - 10(Y + 5) + 5 = 0 \] ### Step 3: Expand the Equation Now, we will expand the equation: 1. Expand \( (X + 4)^2 \): \[ (X + 4)^2 = X^2 + 8X + 16 \] 2. Expand \( (Y + 5)^2 \): \[ (Y + 5)^2 = Y^2 + 10Y + 25 \] 3. Substitute these expansions into the equation: \[ X^2 + 8X + 16 + Y^2 + 10Y + 25 - 8X - 32 - 10Y - 50 + 5 = 0 \] ### Step 4: Combine Like Terms Now, combine all the like terms: \[ X^2 + Y^2 + (8X - 8X) + (10Y - 10Y) + (16 + 25 - 32 - 50 + 5) = 0 \] This simplifies to: \[ X^2 + Y^2 + (16 + 25 - 32 - 50 + 5) = 0 \] Calculating the constant term: \[ 16 + 25 = 41 \] \[ 41 - 32 = 9 \] \[ 9 - 50 = -41 \] \[ -41 + 5 = -36 \] So, we have: \[ X^2 + Y^2 - 36 = 0 \] ### Step 5: Rearranging the Equation Rearranging gives us: \[ X^2 + Y^2 = 36 \] ### Step 6: Relate to the Required Form The equation \( X^2 + Y^2 = K^2 \) implies: \[ K^2 = 36 \] ### Step 7: Find |K| Taking the square root gives: \[ K = \pm 6 \] Thus, the absolute value is: \[ |K| = 6 \] ### Final Answer The value of \( |K| \) is \( 6 \). ---
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Knowledge Check

  • Without changing the direction of the axes, the origin is transferred to the point (2,3). Then the equation x^(2)+y^(2)-4x-6y+9=0 changes to

    A
    `x^(2)+y^(2)+4=0`
    B
    `x^(2)+y^(2)=4`
    C
    `x^(2)+y^(2)-8x-12y+48=0`
    D
    `x^(2)+y^(2)=9`
  • the equation of the axes of the ellispe 3x^(2)+4y^(2)+6x-8y-5=0 are

    A
    `x-3,y=5`
    B
    `x+3=0,y-5=0`
    C
    `x-1=0,y=0`
    D
    `x+1=0,y-1=0`
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