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The points (k-1, k+2),(k , k+1),(k+1, k)...

The points `(k-1, k+2),(k , k+1),(k+1, k)` are collinear for

A

any value of k

B

`k=-1//2` only

C

no value of k

D

integral values of k only

Text Solution

Verified by Experts

The correct Answer is:
A
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Knowledge Check

  • If the points (k,2-k),(-k+1,2k),(-4-k,6-2k) are collinear then k=

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