If silver nitrate solution is added to a salt solution and a yellow precipitate is obtained the salt may contain

Options

A. `Br^(-)`
B. `l^(-)`
C. `Cl^(-)`
D. `F^(-)`

Answer

To solve the problem of identifying the possible ions in a salt solution that produces a yellow precipitate when silver nitrate is added, we can follow these steps:

### Step 1: Understand the Reaction
When silver nitrate (AgNO₃) is added to a salt solution, it reacts with halide ions (Cl⁻, Br⁻, I⁻) to form precipitates. The color of the precipitate can help identify which halide ion is present.

### Step 2: Identify the Precipitate Colors
- **Chloride ions (Cl⁻)**: Form a curdy white precipitate of silver chloride (AgCl).
- **Bromide ions (Br⁻)**: Form a yellow precipitate of silver bromide (AgBr).
- **Iodide ions (I⁻)**: Also form a yellow precipitate of silver iodide (AgI).
- **Fluoride ions (F⁻)**: Do not form a precipitate with silver nitrate.

### Step 3: Analyze the Given Information
Since the problem states that a yellow precipitate is obtained, we can conclude that the salt solution must contain either bromide ions (Br⁻) or iodide ions (I⁻).

### Step 4: Conclusion
Therefore, if a yellow precipitate is obtained upon the addition of silver nitrate to a salt solution, the salt may contain either bromide ions (Br⁻) or iodide ions (I⁻).

### Final Answer
The salt may contain bromide ions (Br⁻) or iodide ions (I⁻).

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