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A: CH(3)CH=CH(2) can undergo cationic po...

A: `CH_(3)CH=CH_(2)` can undergo cationic polymeisation with greater ease than `CH_(2)=CH_(2)`.
R: `CH_(3)-` groups has +I effect.

A

If both Assertion & Reason are true and the reason is the correct explanation of the assertion, then mark 1.

B

If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark 2.

C

If Assertion is true statement but Reason is false, then mark 3.

D

If both Assertion and Reason are false statements the mark 4.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the assertion (A) and reason (R) provided: **Assertion (A):** `CH₃CH=CH₂` can undergo cationic polymerization with greater ease than `CH₂=CH₂`. **Reason (R):** `CH₃-` groups have +I effect. ### Step-by-Step Solution: 1. **Understanding Cationic Polymerization:** - Cationic polymerization involves the formation of a carbocation, which is a positively charged carbon species. The stability of this carbocation is crucial for the ease of polymerization. 2. **Analyzing the Structure of the Monomers:** - The first monomer is propene (`CH₃CH=CH₂`), which has a methyl group (`CH₃`) attached to the carbon of the double bond. - The second monomer is ethene (`CH₂=CH₂`), which does not have any alkyl groups attached to the double bond. 3. **Carbocation Stability:** - The stability of a carbocation increases with the number of alkyl groups attached to the positively charged carbon. This is due to the +I (inductive) effect of alkyl groups, which donate electron density to the positively charged carbon, stabilizing it. - In the case of propene, the carbocation formed after the initial step of cationic polymerization will be a secondary carbocation (due to the presence of one methyl group), which is more stable than the primary carbocation that would form from ethene. 4. **Comparing the Two Monomers:** - For propene: The carbocation formed is CH₃C⁺H-CH₂, which is stabilized by the +I effect of the methyl group. - For ethene: The carbocation formed is CH₂C⁺H-CH₂, which is less stable as it has no alkyl groups to stabilize it. 5. **Conclusion:** - Since the carbocation formed from propene is more stable than that from ethene, propene can undergo cationic polymerization more easily than ethene. 6. **Evaluating the Assertion and Reason:** - Both the assertion (A) and reason (R) are correct. The reason provided explains why the assertion is true, as the +I effect of the `CH₃` group in propene enhances the stability of the carbocation, facilitating the polymerization process. ### Final Answer: - **Assertion (A) is true.** - **Reason (R) is true and is the correct explanation of (A).** ---
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Explain why (CH_3)_3C^+ is more stable than CH_3 CH_(2)^(+) and CH_(3)^(+) is the least stable cation.

A: CH_(3)-CH-CH_(3) has 6. hyperconjugative hydrogens while CH_(3)-CH-CH_(2) -CH_(3) has 5 hyperconjugative hydrogens. R: CH_(3)-CH-CH_(3) is more stable than CH_(3)-CH-CH_(2)- CH

Knowledge Check

  • CH_(3)-CH_(2)-CH=CH_(2) has hybridisation :

    A
    `sp,sp,sp^(2),sp^(2)`
    B
    `sp^(3),sp^(3),sp^(2),sp`
    C
    `sp^(3),sp^(3),sp^(2),sp^(2)`
    D
    `sp^(3),sp^(2),sp^(2),sp`
  • CH_(3)-CH_(2)-CH=Ch_(2) has hybridisation :

    A
    `sp,sp,sp^(2),sp^(2)`
    B
    `sp^(3),sp^(3),sp^(2),sp`
    C
    `sp^(3),sp^(3),sp^(2),sp^(2)`
    D
    `sp^(3),sp^(2),sp^(2),sp`
  • CH_(3)CH_(2)OH can be converted into CH_(3)CHO by ______

    A
    Catalystic hydrogenation
    B
    treatment with `LiAlH_(4)`
    C
    treatment with pyridinium chlorochromate
    D
    treatment with `KMnO_(4)`
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    CH_(3)CH_(2)I is more reactive than CH_(3)CH_(2)Cl towards KCN.

    CH_(3)CH_(2)I is more reactive than CH_(3)CH_(2)Cl towards KCN.

    CH_(3)CH_(2)OH can be converted into CH_(3)CHO by _____.

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