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STATEMENT - 1 : SO(2) turns acidified K(...

STATEMENT - 1 : `SO_(2)` turns acidified `K_(2)Cr_(2)O_(7)` green. And
STATEMENT - 2 : `SO_(2)` converts `Cr_(2)O_(7)^(2-)` ion to `Cr^(+3)` which gives green colour.

A

Statement-1 is True, Statement-2, is True, Statement-2 is a correct explanation for Statement-1

B

Statement-1 is True, Statement-2, is True, Statement-2 is NOT a correct explanation for Statement-1

C

Statement-1 is True, Statement-2 is False

D

Statement-1 is False, Statement-2 is True

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • SO_(2) reduces acidified K_(2)Cr_(2)O_(7) to

    A
    `Cr_(2)(SO_(4))_(3)`
    B
    `CrO_(3)`
    C
    `Cr_(2)O_(3)`
    D
    chromium

  • Alkaline KMnO_(4) and acidified K_(2)Cr_(2)O_(7) are :

    A
    Catalysts
    B
    Reducing agents
    C
    Oxidising agents
    D
    None of these

  • If(X) turns acidified K_(2)Cr_(2)O_(7) solution green , then then X may be

    A
    `SO_(2)`
    B
    `CO_(2)`
    C
    `NO_(2)^(Θ)`
    D
    `Fe^(2+)`

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