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In the nuclear reaction ""(3) Li^(7) + "...

In the nuclear reaction `""_(3) Li^(7) + ""_(1) H^(1) to 2""_(2) He^(4)` . The mass loss is nearly 0.02 amu . Hence the energy released in the process is `x xx 10^(2)` million kcal l mole . (nearly) . Then 'x' is ____

Text Solution

Verified by Experts

The correct Answer is:
4
`Q = ((0.02 xx 931.5 xx 10^(6) xx 1 .602 xx 10^(-19) xx 6 xx 10^(23))/(4 .18 xx 1000)) = 42.84 xx 10^(3+ 4)`
`= 4.284 xx 10^(8)` Kcal/mole = `4.28 xx (10^(8))/(10^(6))` million Kcal/mole = `4 xx 10^(2)` million Kcal/mole
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