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In the sequence of the following nuclear...

In the sequence of the following nuclear reaction `""_(98)^(238) X overset(-alpha)(to) Y overset(-beta)(to) Z overset(-beta) (to)L overset(n alpha) (to) ""_(90)^(218) M`
What is the value of n

A

3

B

4

C

5

D

6

Text Solution

Verified by Experts

The correct Answer is:
B
`""_(98) X^(238) overset(- (""_(2) He^(4)))(to) ""_(96) Y^(234) overset(- (""_(1) beta^(0)))(to) ""_(97) Z^(234) overset(- (""_(1) beta^(0)))(to) ""_(98) Z^(234)`
`""_(98) Z^(234) to ""_(90) Na^(218) + n(""_(2) alpha^(4))`
`234 = 218 + 4n implies n = ((234 - 218)/(4)) = 4 , 98 = 90 + 2n implies n = (8)/(2) = 4`
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