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Weak acids and bases are not completely ...

Weak acids and bases are not completely ionised when dissolved in polar medium like water
`H rarr H^(+) +A^(-)`
`{:(t_(0),C,O,O),(t_(eq),C-Calpha,Calpha,Calpha):}`
`K_(a)=(C alpha^(2))/(1-alpha)=Calpha^(2),alphasqrt((K_(a))/(C))`
`:. (alpha_(1))/(alpha_(2))=sqrt((Ka_(1))/(Ka_(2))),(alpha_(1))/(alpha_(2))=sqrt((C_(2))/(C_(1)))`
( For two acids at same conc.) (for same acid at diff conc. )
`alpha`and `alpha` are in the ratio 1:2 at same conc. `Ka_(1), =2xx 10^(-4)`, what will be `Ka_(2)`,?

A

`8xx10 ^(-4)`

B

` 2xx10 ^(-4)`

C

` 4xx10 ^(-4)`

D

` 1xx10 ^(-4) `

Text Solution

Verified by Experts

The correct Answer is:
A
` (alpha_1)/(alpha_2) = sqrt((Ka_1)/(Ka_2) )rArr (1)/(2) = sqrt((2xx 10 ^(-4) )/(Ka_2)) , Ka_2 = 8xx 10^(-4) `
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