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If n in N and Deltan=|(n!,(n+1)!,(n+2)...

If `n in N` and `Delta_n=|(n!,(n+1)!,(n+2)!),((n+1)!,(n+2)!,(n+3)!),((n+2)!,(n+3)!,(n+4)!)|` then `lim_(n->oo) ((3^(n^3)-5) Delta_n)/(Delta_(n+1)` equals

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