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Write Lewis structure of O(2)^(-) ion an...

Write Lewis structure of `O_(2)^(-)` ion and find out oxidation state of each oxygen atom? What is the average oxidation state of oxygen in this ion?

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To solve the problem, we will follow these steps: ### Step 1: Draw the Lewis Structure of O₂⁻ Ion 1. **Identify the number of valence electrons**: Each oxygen atom has 6 valence electrons. Since there are two oxygen atoms, the total number of valence electrons is: \[ 6 \text{ (from first O)} + 6 \text{ (from second O)} + 1 \text{ (extra electron due to -1 charge)} = 13 \text{ electrons} \] ...
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Knowledge Check

  • Oxygen has an oxidation state of +2 in

    A
    `H_(2)O_(2)`
    B
    `H_(2)O`
    C
    `OF_(2)`
    D
    `SO_(2)`

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