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Match the species given in Column I with...

Match the species given in Column I with the properties mentioned in Column II
`{:(,"Column-I",,"Column-II"),("A.","BF"_(4)^(-),1.,"Oxidation state of central atom is +4"),("B.","AlCl"_(3),2.,"Strong oxidising agent"),("C.","SnO",3.,"Lewis acid"),("D.","PbO"_(2),4.,"Can be further oxidised"),(,,5.,"Tetrahedral shape"):}`

Text Solution

AI Generated Solution

To solve the matching question, we will analyze each species in Column I and determine their corresponding properties in Column II step by step. ### Step 1: Analyze BF₄⁻ - **Species**: BF₄⁻ - **Valence Electrons**: Boron (B) has 3 valence electrons, and there are 4 fluorine (F) atoms, each contributing 1 electron. Since it is an anion (negative charge), we add 1 electron. - **Calculation**: - Total valence electrons = 3 (B) + 4 (F) + 1 (charge) = 8 - Hybridization = (8 / 2) = 4 (indicating sp³ hybridization). ...
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  • Match the compounds given in column I with oxidation states of carbon given in column II and mark the appropriate choice. {:(,"Column I",,"Column II"),("(A)",C_(6)H_(12)O_(6)," (i)"," +3"),("(B)",CHCl_(3)," (ii)"," -3"),("(C)",CH_(3)CH_(3)," (iii)"," +2"),("(D)",(CO OH)_(2)," (iv)"," 0"):}

    A
    (A) `rarr` (iv), (B) `rarr ` (iii), (C) `rarr` (ii), (D) `rarr` (i)
    B
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    C
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    D
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