Draw the structures of `BCl_(3).NH_(3) and AlCl_(3)` (dimer).

Explanation

To solve the question of drawing the structures of BCl₃·NH₃ and AlCl₃ (dimer), we will follow these steps:

### Step 1: Structure of BCl₃·NH₃
1. **Identify the components**: BCl₃ (Boron Trichloride) and NH₃ (Ammonia).
2. **Determine the electron configuration**: Boron in BCl₃ has only 6 electrons in its valence shell, making it electron-deficient (incomplete octet). Ammonia (NH₃) has a lone pair of electrons on the nitrogen atom.
3. **Lewis Acid-Base Interaction**: Since BCl₃ is electron-deficient, it acts as a Lewis acid, while NH₃, which has a lone pair, acts as a Lewis base. The lone pair from nitrogen will be donated to boron.
4. **Draw the structure**:
- Start with BCl₃: Boron (B) at the center with three chlorine (Cl) atoms bonded to it.
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