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The units vectors orthogonal to the vect...

The units vectors orthogonal to the vector `- hat i + 2hat j + 2hat k` and making equal angles with the X and Y axes islare) :

A

`+-1/3(2hati+2hatj-hatk)`

B

`19/(5sqrt43)`

C

`+-1/3(hati+hatj-hatk)`

D

none of these

Text Solution

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The correct Answer is:
To find the unit vectors orthogonal to the vector \(-\hat{i} + 2\hat{j} + 2\hat{k}\) and making equal angles with the X and Y axes, we can follow these steps: ### Step 1: Define the Unit Vector Let the required unit vector be represented as: \[ \vec{R} = l\hat{i} + m\hat{j} + n\hat{k} \] where \(l\), \(m\), and \(n\) are the direction cosines of the vector. ### Step 2: Use the Unit Vector Condition Since \(\vec{R}\) is a unit vector, it must satisfy the equation: \[ l^2 + m^2 + n^2 = 1 \tag{1} \] ### Step 3: Equal Angles with X and Y Axes The problem states that the vector makes equal angles with the X and Y axes, which implies: \[ l = m \tag{2} \] ### Step 4: Substitute Equation (2) into Equation (1) Substituting \(m = l\) into equation (1): \[ l^2 + l^2 + n^2 = 1 \] This simplifies to: \[ 2l^2 + n^2 = 1 \tag{3} \] ### Step 5: Orthogonality Condition The vector \(\vec{R}\) is orthogonal to the vector \(-\hat{i} + 2\hat{j} + 2\hat{k}\). Therefore, their dot product must be zero: \[ \vec{R} \cdot (-\hat{i} + 2\hat{j} + 2\hat{k}) = 0 \] Calculating the dot product: \[ l(-1) + m(2) + n(2) = 0 \] Substituting \(m = l\): \[ -l + 2l + 2n = 0 \] This simplifies to: \[ l + 2n = 0 \tag{4} \] ### Step 6: Substitute Equation (4) into Equation (3) From equation (4), we can express \(n\) in terms of \(l\): \[ n = -\frac{l}{2} \] Now substitute this into equation (3): \[ 2l^2 + \left(-\frac{l}{2}\right)^2 = 1 \] This simplifies to: \[ 2l^2 + \frac{l^2}{4} = 1 \] Multiplying through by 4 to eliminate the fraction: \[ 8l^2 + l^2 = 4 \] Thus: \[ 9l^2 = 4 \implies l^2 = \frac{4}{9} \implies l = \pm \frac{2}{3} \] ### Step 7: Find \(m\) and \(n\) Since \(m = l\): \[ m = \pm \frac{2}{3} \] Now substituting \(l\) back into equation (4) to find \(n\): \[ n = -\frac{l}{2} = -\frac{\pm \frac{2}{3}}{2} = \mp \frac{1}{3} \] ### Step 8: Write the Final Unit Vectors Thus, the unit vectors orthogonal to the given vector and making equal angles with the X and Y axes are: \[ \vec{R} = \pm \left(\frac{2}{3}\hat{i} + \frac{2}{3}\hat{j} - \frac{1}{3}\hat{k}\right) \] ### Final Answer The required unit vectors are: \[ \frac{2}{3}\hat{i} + \frac{2}{3}\hat{j} - \frac{1}{3}\hat{k} \quad \text{and} \quad -\left(\frac{2}{3}\hat{i} + \frac{2}{3}\hat{j} - \frac{1}{3}\hat{k}\right) \]

To find the unit vectors orthogonal to the vector \(-\hat{i} + 2\hat{j} + 2\hat{k}\) and making equal angles with the X and Y axes, we can follow these steps: ### Step 1: Define the Unit Vector Let the required unit vector be represented as: \[ \vec{R} = l\hat{i} + m\hat{j} + n\hat{k} \] where \(l\), \(m\), and \(n\) are the direction cosines of the vector. ...
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The unit vector orthogonal to vector -hat i+ hat j+2 hat k and making equal angles with the x and y-axis a. +-1/3(2 hat i+2 hat j- hat k) b. +-1/3( hat i+ hat j- hat k) c. +-1/3(2 hat i-2 hat j- hat k) d. none of these

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Knowledge Check

  • Unit vector along the vector hat(i) + hat(j) + hat(k) is

    A
    `(1)/(3) (hat(i) + hat(k) + hat(k))`
    B
    `(1)/(2) (hat(i) + hat(j) + hat(k))`
    C
    `(1)/(sqrt3) (hat(i) + hat(j) + hat(k))`
    D
    `(1)/(sqrt2) (hat(i) + hat(j) + hat(k))`
  • The vector in the direction of the vector hat(i) - 2 hat(j) + 2hat(k) that has magnitude 9 units is

    A
    `hat(i) - 2 hat(j) + 2 hat(k)`
    B
    `(hat(i) - 2 hat(j) + 2 hat(k))/(3)`
    C
    `3( hat(i)- 2 hat(j) + 2 hat(k))`
    D
    `9 ( hat(i) - 2 hat(j) + 2 hat(k))`
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