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In an equilateral triangle, the inradius...

In an equilateral triangle, the inradius, circumradius, and one of the exradii are in the ratio

A

`2: 4:5`

B

`1:2:3`

C

`1:2:4`

D

`2:4:3`

Text Solution

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The correct Answer is:
To solve the problem of finding the ratio of the inradius, circumradius, and one of the exradii of an equilateral triangle, we can follow these steps: ### Step 1: Define the properties of the equilateral triangle Let the side length of the equilateral triangle be \( a \). In an equilateral triangle, all sides are equal, and we can denote the sides as \( a = b = c \). ### Step 2: Calculate the area of the triangle The area \( \Delta \) of an equilateral triangle is given by the formula: \[ \Delta = \frac{\sqrt{3}}{4} a^2 \] ### Step 3: Calculate the semi-perimeter \( S \) The semi-perimeter \( S \) of the triangle is given by: \[ S = \frac{a + b + c}{2} = \frac{3a}{2} \] ### Step 4: Calculate the inradius \( r \) The inradius \( r \) can be calculated using the formula: \[ r = \frac{\Delta}{S} \] Substituting the values from Steps 2 and 3: \[ r = \frac{\frac{\sqrt{3}}{4} a^2}{\frac{3a}{2}} = \frac{\sqrt{3} a^2}{4} \cdot \frac{2}{3a} = \frac{a}{2\sqrt{3}} \] ### Step 5: Calculate the circumradius \( R \) The circumradius \( R \) can be calculated using the formula: \[ R = \frac{abc}{4\Delta} \] For an equilateral triangle, this simplifies to: \[ R = \frac{a \cdot a \cdot a}{4 \cdot \frac{\sqrt{3}}{4} a^2} = \frac{a^3}{\sqrt{3} a^2} = \frac{a}{\sqrt{3}} \] ### Step 6: Calculate one of the exradii \( r_1 \) The exradius \( r_1 \) can be calculated using the formula: \[ r_1 = \frac{\Delta}{S - a} \] Substituting the values: \[ r_1 = \frac{\frac{\sqrt{3}}{4} a^2}{\frac{3a}{2} - a} = \frac{\frac{\sqrt{3}}{4} a^2}{\frac{a}{2}} = \frac{\sqrt{3}}{2} a \] ### Step 7: Find the ratio of \( r : R : r_1 \) Now we have: - \( r = \frac{a}{2\sqrt{3}} \) - \( R = \frac{a}{\sqrt{3}} \) - \( r_1 = \frac{\sqrt{3}}{2} a \) To find the ratio, we can express them in terms of \( a \): \[ r : R : r_1 = \frac{a}{2\sqrt{3}} : \frac{a}{\sqrt{3}} : \frac{\sqrt{3}}{2} a \] Dividing each term by \( a \): \[ \frac{1}{2\sqrt{3}} : \frac{1}{\sqrt{3}} : \frac{\sqrt{3}}{2} \] ### Step 8: Simplify the ratio To simplify: 1. Multiply each term by \( 2\sqrt{3} \): \[ 1 : 2 : 3 \] Thus, the ratio of the inradius, circumradius, and one of the exradii in an equilateral triangle is: \[ 1 : 2 : 3 \] ### Final Answer The correct option is \( 1 : 2 : 3 \).

To solve the problem of finding the ratio of the inradius, circumradius, and one of the exradii of an equilateral triangle, we can follow these steps: ### Step 1: Define the properties of the equilateral triangle Let the side length of the equilateral triangle be \( a \). In an equilateral triangle, all sides are equal, and we can denote the sides as \( a = b = c \). ### Step 2: Calculate the area of the triangle The area \( \Delta \) of an equilateral triangle is given by the formula: \[ ...
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Knowledge Check

  • The regular hexagon shown above is divided into six congruent equilateral triangle. What is the measure, in degrees, of one of the interior angles of the hexagon?

    A
    `60^@`
    B
    `120^@`
    C
    `180^@`
    D
    `360^@`
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