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Regular pentagons are inscribed in two c...

Regular pentagons are inscribed in two circles of radius `5 `and `2` units respectively. The ratio of their areas is

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To find the ratio of the areas of two regular pentagons inscribed in circles of radius 5 units and 2 units respectively, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Area Formula for a Regular Pentagon:** The area \( A \) of a regular pentagon inscribed in a circle of radius \( r \) can be calculated using the formula: \[ A = \frac{5}{2} r^2 \sin(72^\circ) \] where \( r \) is the radius of the circumscribed circle. 2. **Calculate the Area of the First Pentagon:** For the first pentagon inscribed in the circle of radius \( r_1 = 5 \): \[ A_1 = \frac{5}{2} (5^2) \sin(72^\circ) = \frac{5}{2} \cdot 25 \cdot \sin(72^\circ) = \frac{125}{2} \sin(72^\circ) \] 3. **Calculate the Area of the Second Pentagon:** For the second pentagon inscribed in the circle of radius \( r_2 = 2 \): \[ A_2 = \frac{5}{2} (2^2) \sin(72^\circ) = \frac{5}{2} \cdot 4 \cdot \sin(72^\circ) = 10 \sin(72^\circ) \] 4. **Find the Ratio of the Areas:** To find the ratio of the areas \( \frac{A_1}{A_2} \): \[ \frac{A_1}{A_2} = \frac{\frac{125}{2} \sin(72^\circ)}{10 \sin(72^\circ)} \] The \( \sin(72^\circ) \) cancels out: \[ \frac{A_1}{A_2} = \frac{125/2}{10} = \frac{125}{20} = \frac{25}{4} \] 5. **Conclusion:** The ratio of the areas of the two regular pentagons is: \[ \frac{A_1}{A_2} = \frac{25}{4} \]

To find the ratio of the areas of two regular pentagons inscribed in circles of radius 5 units and 2 units respectively, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Area Formula for a Regular Pentagon:** The area \( A \) of a regular pentagon inscribed in a circle of radius \( r \) can be calculated using the formula: \[ A = \frac{5}{2} r^2 \sin(72^\circ) ...
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Knowledge Check

  • Find the area of a circle of radius 5.6 cm.

    A
    `58.56 cm^(2)`.
    B
    `78.56 cm^(2)`.
    C
    `98.56 cm^(2)`.
    D
    `88.56 cm^(2)`.
  • Shown below is a regular hexagon inscribed in a circle whose radius is 4 inches . What is the perimeter, in inches, of the hexagon?

    A
    `8 pi`
    B
    `12sqrt(3)`
    C
    `18`
    D
    `24`
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