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If any quadrilateral ABCD, prove that "...

If any quadrilateral ABCD, prove that `"sin"(A+B)+sin(C+D)=0` `"cos"(A+B)=cos(C+D)`

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To prove the given statements for any quadrilateral ABCD, we will follow a systematic approach using trigonometric identities and properties of angles in a quadrilateral. ### Step 1: Understanding the Angles in a Quadrilateral In any quadrilateral, the sum of the interior angles is equal to \(2\pi\) radians (or \(360^\circ\)). Therefore, we can write: \[ A + B + C + D = 2\pi \] ...
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