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If 5tantheta =4," then " (5sintheta-3cos...

If `5tantheta =4," then " (5sintheta-3costheta)/(5sintheta+2costheta)` is equal to

A

0

B

1

C

`1/6`

D

6

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AI Generated Solution

The correct Answer is:
To solve the problem, we start with the given equation and manipulate it step by step. **Step 1: Start with the given equation.** We know that: \[ 5 \tan \theta = 4 \] From this, we can find: \[ \tan \theta = \frac{4}{5} \] **Step 2: Rewrite the expression we need to evaluate.** We need to find the value of: \[ \frac{5 \sin \theta - 3 \cos \theta}{5 \sin \theta + 2 \cos \theta} \] **Step 3: Divide both the numerator and the denominator by \(\cos \theta\).** This gives us: \[ \frac{\frac{5 \sin \theta}{\cos \theta} - \frac{3 \cos \theta}{\cos \theta}}{\frac{5 \sin \theta}{\cos \theta} + \frac{2 \cos \theta}{\cos \theta}} \] **Step 4: Simplify the fractions.** Using the identity \(\tan \theta = \frac{\sin \theta}{\cos \theta}\), we can rewrite the expression as: \[ \frac{5 \tan \theta - 3}{5 \tan \theta + 2} \] **Step 5: Substitute the value of \(\tan \theta\).** Now, substitute \(\tan \theta = \frac{4}{5}\): \[ \frac{5 \left(\frac{4}{5}\right) - 3}{5 \left(\frac{4}{5}\right) + 2} \] **Step 6: Simplify the expression.** Calculating the numerator: \[ 5 \left(\frac{4}{5}\right) - 3 = 4 - 3 = 1 \] Calculating the denominator: \[ 5 \left(\frac{4}{5}\right) + 2 = 4 + 2 = 6 \] **Step 7: Write the final result.** Thus, we have: \[ \frac{1}{6} \] Therefore, the value of the expression \(\frac{5 \sin \theta - 3 \cos \theta}{5 \sin \theta + 2 \cos \theta}\) is \(\frac{1}{6}\). ---

To solve the problem, we start with the given equation and manipulate it step by step. **Step 1: Start with the given equation.** We know that: \[ 5 \tan \theta = 4 \] From this, we can find: \[ \tan \theta = \frac{4}{5} \] ...
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CENGAGE ENGLISH-TRIGONOMETRIC FUNCTIONS -Exercises
  1. If 5tantheta =4," then " (5sintheta-3costheta)/(5sintheta+2costheta) i...

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  2. If tantheta =-4/3," then " sintheta is

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  3. If sinx+cosecx=2," then "sin^nx+cosec^nx is equal to

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  4. If tantheta+sintheta=mandtantheta-sintheta=n,then

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  5. If cosectheta-cottheta=q, then the value of cosectheta is

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  6. If (sinx)/a=(cosx)/b=(tanx)/c=k , then b c+1/(c k)+(a k)/(1+b k) is eq...

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  7. If sec^4theta+sec^2theta=10+tan^4theta+tan^2theta", then "sin^2theta=

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  8. If x=(2sintheta)/(1+costheta+sintheta),t h e n(1-costheta+sintheta)/(1...

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  9. If secalpha and cosecalpha are the roots of the equation x^2-px+q=0, t...

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  10. Which of the following is not the quadratic equation whose roots are c...

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  11. If sinx+sin^2x=1, then find the value of cos^(12)x +3cos^(10)x + 3 cos...

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  12. 3(sintheta-costheta)^(4)+6(sintheta+costheta)^(2)+4(sin^(6)theta+cos^(...

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  13. If sinx+sin^2x=1 then the value of tan^8x-tan^4x-2tan^2x+1 will be equ...

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  14. (1+tanalphatanbeta)^2+(tanalpha-tanbeta)^2=

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  15. Let A0A1A2A3A4A5 be a regular hexagon inscribed in a circle of unit ra...

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  16. A circle is drawn in a sectore of a larger circle of radius r, as show...

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  17. A right triangle has perimeter of length 7 and hypotenuse of length 3....

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  18. Given that the side length of a rhombus is the geometric mean of the ...

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  19. Which of the following is correct?

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  20. The equation sin^2theta=(x^2+y^2)/(2x y),x , y!=0 is possible if

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