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Let a,b,c be the sides of a triangle ABC...

Let a,b,c be the sides of a triangle ABC, a=2c,cos(A-C)+cos B=1. then the value of C is

A

`pi//6`

B

`pi//3`

C

`2pi//3`

D

`5pi//6`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the value of angle \( C \) given the conditions \( a = 2c \) and \( \cos(A - C) + \cos B = 1 \). ### Step-by-Step Solution: 1. **Write down the given conditions:** We know that: - \( a = 2c \) - \( \cos(A - C) + \cos B = 1 \) 2. **Use the angle sum property of triangles:** The angles in a triangle sum up to \( 180^\circ \): \[ A + B + C = 180^\circ \] Thus, we can express \( B \) in terms of \( A \) and \( C \): \[ B = 180^\circ - A - C \] 3. **Substitute \( B \) into the cosine equation:** Using the cosine of the angle difference: \[ \cos B = \cos(180^\circ - A - C) = -\cos(A + C) \] Substitute this into the equation: \[ \cos(A - C) - \cos(A + C) = 1 \] 4. **Use the cosine subtraction and addition formulas:** The cosine subtraction and addition formulas are: \[ \cos(A - C) = \cos A \cos C + \sin A \sin C \] \[ \cos(A + C) = \cos A \cos C - \sin A \sin C \] Substitute these into the equation: \[ (\cos A \cos C + \sin A \sin C) - (\cos A \cos C - \sin A \sin C) = 1 \] Simplifying gives: \[ 2 \sin A \sin C = 1 \] 5. **Express \( A \) in terms of \( C \):** From the sine rule: \[ \frac{a}{\sin A} = \frac{c}{\sin C} \] Since \( a = 2c \): \[ \frac{2c}{\sin A} = \frac{c}{\sin C} \] This simplifies to: \[ 2 \sin C = \sin A \quad \text{(1)} \] 6. **Substitute \( \sin A \) into the equation:** Substitute equation (1) into \( 2 \sin A \sin C = 1 \): \[ 2(2 \sin C) \sin C = 1 \] This simplifies to: \[ 4 \sin^2 C = 1 \] Thus: \[ \sin^2 C = \frac{1}{4} \] 7. **Find the values of \( C \):** Taking the square root gives: \[ \sin C = \frac{1}{2} \] The angles for which \( \sin C = \frac{1}{2} \) are: \[ C = 30^\circ \quad \text{or} \quad C = 150^\circ \] 8. **Determine the valid angle for a triangle:** Since \( C \) must be an angle in a triangle, we discard \( 150^\circ \) (as it would make the sum of angles exceed \( 180^\circ \)). Therefore: \[ C = 30^\circ \] ### Final Answer: The value of \( C \) is \( 30^\circ \).

To solve the problem, we need to find the value of angle \( C \) given the conditions \( a = 2c \) and \( \cos(A - C) + \cos B = 1 \). ### Step-by-Step Solution: 1. **Write down the given conditions:** We know that: - \( a = 2c \) - \( \cos(A - C) + \cos B = 1 \) ...
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