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If the roots of the equation b x^2+""c x...

If the roots of the equation `b x^2+""c x""+""a""=""0` be imaginary, then for all real values of x, the expression `3b^2x^2+""6b c x""+""2c^2` is (1) greater than 4ab (2) less than 4ab (3) greater than `4a b` (4) less than `4a b`

A

greater than 4ab.

B

less then 4ab

C

grreater than - 4ab.

D

less than - 4ab.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given quadratic equation and the expression provided. ### Step-by-Step Solution: 1. **Identify the Condition for Imaginary Roots**: The roots of the quadratic equation \( bx^2 + cx + a = 0 \) are imaginary if the discriminant is less than zero. The discriminant \( D \) is given by: \[ D = c^2 - 4ab \] For the roots to be imaginary: \[ c^2 - 4ab < 0 \quad \Rightarrow \quad c^2 < 4ab \] **Hint**: Remember that the discriminant must be negative for the roots to be imaginary. 2. **Consider the Expression**: We need to analyze the expression: \[ E = 3b^2x^2 + 6bcx + 2c^2 \] This is a quadratic expression in terms of \( x \). 3. **Find the Discriminant of the Expression**: The discriminant of the expression \( E \) can be computed as follows: \[ D_E = (6bc)^2 - 4(3b^2)(2c^2) \] Simplifying this: \[ D_E = 36b^2c^2 - 24b^2c^2 = 12b^2c^2 \] **Hint**: The discriminant of a quadratic expression helps determine the nature of its roots. 4. **Determine the Nature of the Expression**: Since \( D_E = 12b^2c^2 \) is always non-negative (as \( b^2 \) and \( c^2 \) are always non-negative), the expression \( E \) will always have real roots. 5. **Find the Minimum Value of the Expression**: The minimum value of a quadratic expression \( ax^2 + bx + c \) occurs at: \[ x = -\frac{b}{2a} \] For our expression: \[ x = -\frac{6bc}{2 \cdot 3b^2} = -\frac{c}{b} \] Plugging this value back into \( E \): \[ E\left(-\frac{c}{b}\right) = 3b^2\left(-\frac{c}{b}\right)^2 + 6bc\left(-\frac{c}{b}\right) + 2c^2 \] Simplifying: \[ = 3b^2\frac{c^2}{b^2} - 6c^2 + 2c^2 = 3c^2 - 6c^2 + 2c^2 = -c^2 \] 6. **Compare with \( 4ab \)**: Since we know \( c^2 < 4ab \), we can conclude: \[ -c^2 > -4ab \quad \Rightarrow \quad E \text{ is greater than } 4ab \] ### Conclusion: Thus, the expression \( 3b^2x^2 + 6bcx + 2c^2 \) is greater than \( 4ab \). The correct option is: (1) greater than \( 4ab \).

To solve the problem, we need to analyze the given quadratic equation and the expression provided. ### Step-by-Step Solution: 1. **Identify the Condition for Imaginary Roots**: The roots of the quadratic equation \( bx^2 + cx + a = 0 \) are imaginary if the discriminant is less than zero. The discriminant \( D \) is given by: \[ D = c^2 - 4ab ...
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