Let ABCD is a parallelogram and vec AC,vec BD be its diagonal,then vec AC+vec BD is

ABCD is a parallelogram and AC, BD are its diagonals. Show that : vec(AC)+vec(BD)=2vec(BC), vec(AC)-vec(BD)=2vec(AB) .

If vec a and vec b represent two adjacent sides vec AB and vec BC respectively of a parallelogram ABCD, then show that its diagonals vec AC and vec DB are equal to vec a+vec b and vec a-vec b respectively.

ABCD is a parallelogram Fig. 2 (c ) .64. AC and (BD) are its diagonals. Show that (a) vec (AC) +vec (BD) =2 vec (BC) (b) vec (AC) - vec (BD) =2 vec (AB) .

ABCD is a parallelogram where AC and BD are the diagonals. If /_ BAD = 60^(@), /_ ABD = 90^(@) , then what is BD^(2) equal to ?

If G is the intersection of diagonals of a parallelogram ABCD and O is any point, then O vecA + O vec B + O vec C + vec (OD) =

If G is the intersection of diagonals of a parallelogram ABCD and O is any point, then O vecA + O vec B + O vec C + vec (OD) =