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The work function of potassium is 2.0 eV...

The work function of potassium is 2.0 eV. When it is illuminated by light of wavelength `3300A^(@)` photo electrons are emitted. The stopping potential of photo electrons is [Plank’s constant `h=6.6xx10^(-34)Js,1eV=1.6xx10^(-19)J,C=3xx10^(8)ms^(-1)`]

A

0.75V

B

1.75 V

C

2.5 V

D

3.75 V

Text Solution

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The correct Answer is:
B
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Work function of a metal is 3.0 eV. It is illuminated by a light of wavelength 3xx10^(-7) m. Calculate the maximum energy of the electron.

The work function of a metal is 3.0 V. It is illuminated by a light of wave length 3xx10^(-7)m . Calculate i) threshold frequency, ii) the maximum energy of photoelectrons, iii) the stopping potential. (h=6.63xx10^(-34)Js and c=3xx10^(8)ms^(-)) .

Knowledge Check

  • The work function of the nickel is 5 eV. When a light of wavelength 2000 Å falls on it ,it emits photoelectrons in the circuit .Then, the potential difference necessary to stop the faster electrons emitted is (Given , h=6.67xx10^(-34)J-s)

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    B
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    C
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    D
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  • The work function of a certain metal is 3.31xx10^(-19)J . Then the maximum kinetic energy of photoelectrons emitted by incident radiation of wavelength 5000Å is (given h=6.62xx10^(34)J-s,C=3xx10^(8)ms^(-1),e=1.6xx10^(-19) coul.)

    A
    2.48 eV
    B
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    C
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    D
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  • The photo electric work function of a metal is 1 eV. Light of wave length lamda=3000A^(@) falls on it. The velocity of emitted photo electron is approximately

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