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A light string passing over a smooth lig...

A light string passing over a smooth light pulley connects two blocks of masses `m_1` and `m_2` (vertically). If the acceleration of the system is `g//8`, then the ratio of the masses is

A

`8:1`

B

`9:7`

C

`4:3`

D

`5:3`

Text Solution

Verified by Experts

The correct Answer is:
B
The acceleration of the system is
`a=((m_1 -m_2 ) g) /(m_1 +m_2)=(g)/(8) or (m_1 -m_2 )/(m_1 +m_2) = 1/8`
`or 8m_1- 8m_2 =m_1 +m_2 or 7 m_1 = 9m_2 or (m_1 )/(m_2)=(9)/(7)`
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Knowledge Check

  • A light string passing over a smooth light pulley connects two blocks of masses m_(1) and m_(2) (vertically). If the acceleration of the system is g//8 , then the ratio of masses is

    A
    `8:1`
    B
    `4:3`
    C
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    D
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    `sintheta=2m_2/m_1` , `N=m_1g cos theta`
    B
    `sintheta=m_2/m_1` , `N=m_1g cos theta`
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