If galvanic cell is formed by standard hydrogen electrode with by `E_(Cu^(2+)|Cu)^(Theta)=+0.34V ` in standard condition, so what is `Cu^(2+)|Cu` electrode ?

Options

A. Anode electrode, negative electrode
B. Cathode electrode, positive electrode
C. None of above
D. Anode positive electrode

Answer

B

Explanation

(a) `E_(cell)^(Theta)=E_("Cathod")^(Theta)-E_("Anode")^(Theta)`
`=E_(H^(+)|H_(2))^(Theta)-E_(Cu^(2+)|Cu)^(Theta)`
`=0.0-(0.34)=0.34V(A)` is wrong
(b) `E_(cell)^(Theta)=E_("Cathod")^(Theta)-E_("Anode")^(Theta)`
`=E_(Cu^(2+)|Cu)^(Theta)-E_(H^(+)|H_(2))^(Theta)`
`=0.34-0.0=0.34V` So, (B) is true.
Means, `Cu^(2+)|Cu` Cathode (Positive) electrode and `H^(+)|H_(2)` anode.