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If emf of standard cell during cell reac...

If emf of standard cell during cell reaction is 0.295 V at 298 K and n=2, then what is the equilibrium constant of such reaction ? `[F=96500," "R=8.314KJ^(-1)mol^(-1)]`

A

`4.0xx10^(12)`

B

`1.0xx10^(2)`

C

`1.0xx10^(10)`

D

`2.0xx10^(11)`

Text Solution

Verified by Experts

The correct Answer is:
C
`logK=(nF)/(0.059)`
`therefore logK=(2xx0.295)/(0.059)=10`
`therefore K=1xx10^(10)`.
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