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The energy required to charge a parallel...

The energy required to charge a parallel plate condenser of plate separtion `d` and plate area of cross-section `A` such that the unifom field between the plates is `E` is

A

`(1/2 epsilon_circ E^2)/(Ad)`

B

`1/2 epsilon_circ E^2 Ad`

C

`epsilon_circ E^2 Ad`

D

`(epsilon_circ E^2)/ (Ad)`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • To reduce the capacity of a parallel plate condenser, separation between the plates is

    A
    reduced and area of the plates decreased
    B
    decreased and area of the plates increased
    C
    increased and area of the plates decreased
    D
    increased and area of the plates increased

  • In a parallel-plate capacitor of plate area A , plate separation d and charge Q the force of attraction between the plates is F .

    A
    `F propQ^(2)`
    B
    `F prop 1/A`
    C
    `F prop d`
    D
    `F prop 1/d`

  • A dielectric introduced between the plates of parallel plate condenser

    A
    decreases the electric field between the plates
    B
    decreases the capacity of the condenser
    C
    increases the charge stored in the condenser
    D
    increases the capacity of the condenser

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