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A big ball of mass M , moving with veloc...

A big ball of mass M , moving with velocity u strikes a small ball of mass m , which is at rest. Finally small ball obtains velocity u and big ball v . Then what is the value of v

A

`(M-m)/(M+m)u`

B

`(m)/(M+m)u`

C

`(2m)/(M+m)u`

D

`(M)/(M+m)u`

Text Solution

Verified by Experts

The correct Answer is:
A

From the formulae `v_(1)= ((m_(1)-m_(2))/(m_(1) + m_(2))) u_(1)`
We get `v= ((M-m)/(M + m))u`
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Knowledge Check

  • A ball of mass m moving with a constant velocity strikes against a ball of same mass at rest. If e= coefficient of restitution, then what will the the ratio of the velocities of the two balls after collision?

    A
    `(1-e)/(1+e)`
    B
    `(e-1)/(e+1)`
    C
    `(1+e)/(1-e)`
    D
    `(2+e)/(e-1)`

  • A ball of mass moving with a velocity u collides head on with a ball B of mass m at rest. If the coefficient of restitution is e. the ratio of final velocity of B to the initial velocity of A is

    A
    `(1-e)/(1+e)`
    B
    `(1+e)/(1-e)`
    C
    `(1+e)/2`
    D
    `(1-e)/2`

  • A ball of mass m moving with velocity v collides head-on which the second ball of mass m at rest. I the coefficient of restitution is e and velocity of first ball after collision is v_(1) and velocity of second ball after collision is v_(2) then

    A
    `v_(1)=((1-e)u)/(2),v_(2)=((1+e)u)/(2)`
    B
    `v_(1)=((1+e)u)/(2),v_(2)=((1-e)u)/(2)`
    C
    `v_(1)=u/2,v_(2)=-u/2`
    D
    `v_(1)=(1+e)u,v_(2)=(1-e)u`

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