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A mass of 100 g strikes the wall with sp...

A mass of 100 g strikes the wall with speed `5 m//s` at an angle as shown in figure and it rebounds with the same speed it the contact time is `2 xx 10^(-3) sec`. What is the force applied on the mass by the wall :

A

`250sqrt3` N to right

B

250 N to right

C

`250sqrt3` N to left

D

250 N to left

Text Solution

Verified by Experts

The correct Answer is:
C
Force= Rate of change of momentum
Initial momentum `vec(P)_(1)= mv sin theta hat(i) + mv cos theta hat(j)`
Final momentum `vec(P)_(2)= -mv sin theta hat(i) + mv cos theta hat(j)`
`therefore vec(F)= (Delta vec(P))/(Delta t)= (-2mv sin theta)/(2 xx 10^(-3))`
Substituting `m= 0.1kg, v= 5 m//s, theta= 60^(@)`
Force on the ball `vec(F)= -250 sqrt3N`
Negative sign indicates direction of the force.
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Knowledge Check

  • A mass of 100 g strikes the wall with speed 5 m s^(-1) at an angle as shown in figure and it rebounds with the same speed. If the contact time is 2xx 10^(-3) what is the force applied by the wall?

    A
    `250 sqrt(3)` to right
    B
    250 N to right
    C
    `250 sqrt(3)` N to left
    D
    250 N to left

  • A mass of 100g strikes the wall with speed 5ms^-1 at an angle as shown in figure and it rebounds With the same speed . If the contact time is 2 times 10^-3 sec , what is the force applied by the wall?

    A
    `250sqrt3` to right
    B
    250N to right
    C
    `250 sqrt3N` to left
    D
    250 N to left

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    B
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    C
    `300sqrt(3) N`
    D
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