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A particle of mass m moving eastward wit...

A particle of mass `m` moving eastward with a velocity `V` collides with another particle of same mass moving northwards with the same speed `V`. The two particles coalesce and the new particle moves in NE direction. Calculate magnitude and direction of velocity of new particle.

A

`v//2`

B

2v

C

`v//sqrt(2)`

D

v

Text Solution

Verified by Experts

The correct Answer is:
C

Initial momentum of the system
`vec(P)_(i)= mv hat(i) + mv hat(j)`
`|vec(P)_(i)|= sqrt2mv`
Final momentum of the system = 2mV
By the law of conservation of momentum
`sqrt2mv= 2mV rArr V= (v)/(sqrt2)`
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Knowledge Check

  • A particle of mass 10 kg moving eastwards with a speed 5 ms^(-1) collides with another particle of the same mass moving north-wards with the same speed 5 ms^(-1) .The two particles coalesce on collision.The new particle of mass 20 kg will move in the north-east direction with velocity

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