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Speed of sound in air is 330 m//s. Frequ...

Speed of sound in air is `330 m//s`. Frequancy of Anoop's voice is `1000 Hz` and of Shibham's voice is `2000 Hz`. Find the wavelength corresponding to their voice.

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To find the wavelength corresponding to Anoop's and Shubham's voices, we can use the formula for wavelength: \[ \text{Wavelength} (\lambda) = \frac{\text{Speed of Sound} (v)}{\text{Frequency} (f)} \] ### Step-by-Step Solution: 1. **Identify the given values:** - Speed of sound in air, \( v = 330 \, \text{m/s} \) - Frequency of Anoop's voice, \( f_A = 1000 \, \text{Hz} \) - Frequency of Shubham's voice, \( f_S = 2000 \, \text{Hz} \) 2. **Calculate the wavelength for Anoop's voice:** - Use the formula: \[ \lambda_A = \frac{v}{f_A} \] - Substitute the values: \[ \lambda_A = \frac{330 \, \text{m/s}}{1000 \, \text{Hz}} = 0.33 \, \text{m} \] 3. **Calculate the wavelength for Shubham's voice:** - Use the same formula: \[ \lambda_S = \frac{v}{f_S} \] - Substitute the values: \[ \lambda_S = \frac{330 \, \text{m/s}}{2000 \, \text{Hz}} = 0.165 \, \text{m} \] 4. **Summarize the results:** - Wavelength of Anoop's voice, \( \lambda_A = 0.33 \, \text{m} \) - Wavelength of Shubham's voice, \( \lambda_S = 0.165 \, \text{m} \) ### Final Answer: - Anoop's wavelength: \( 0.33 \, \text{m} \) - Shubham's wavelength: \( 0.165 \, \text{m} \)

To find the wavelength corresponding to Anoop's and Shubham's voices, we can use the formula for wavelength: \[ \text{Wavelength} (\lambda) = \frac{\text{Speed of Sound} (v)}{\text{Frequency} (f)} \] ### Step-by-Step Solution: ...
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