Home
Class 11
PHYSICS
Figure shows a string of linear mass den...

Figure shows a string of linear mass density `1.0g cm^(-1)` on which a wave pulse is travelling. Find the time taken by pulse in travelling through a distance of `50 cm` on the string. Take `g = 10 ms^(-2)`

Text Solution

Verified by Experts

The tension in the string is `F = mg = 10 N`. The mass per unit length is
`mu = 1.0 g cm^(-1) = 0.1 kg m^(-1)`. The wave velocity is, therefore, `v = sqrt(Fmu) = sqrt((10N)/(0.1 kg m^(-1))) = 10 ms^(-1)`. The time taken by the pulse in travelling through `50 cm` is, therefore `0.05 s`.
Promotional Banner

Topper's Solved these Questions

  • WAVE MOTION

    DC PANDEY ENGLISH|Exercise Exercise 17.6|6 Videos

  • WAVE MOTION

    DC PANDEY ENGLISH|Exercise Level 1 Assertion And Reason|10 Videos

  • WAVE MOTION

    DC PANDEY ENGLISH|Exercise Exercise 17.4|2 Videos

  • VECTORS

    DC PANDEY ENGLISH|Exercise Medical enrances gallery|9 Videos

  • WORK, ENERGY & POWER

    DC PANDEY ENGLISH|Exercise Level 2 Comprehension Based|2 Videos

Similar Questions

Explore conceptually related problems

Figure showa a string of linear mass density 1.0gcm^-1 on which a wave pulse is travelling. Find the time taken by the pulse in travelling through a distance of 50 cm on the string. Take g=10 ms^-2 .

A way pulse is travelling on a string of linear mass density 6.4 xx 10^(-3)kg m^(-1) under a load of 80 kgf . Calculate the time taken by the pulse to traverse the string, if its length is 0.7 m .

Find the tension in the horizontal string PQ and the string QR in the given figure [ Take g = 10 m//s^(2) ]

Find the tension in the horizontal string PQ and the string QR in the given figure. [Take g=10m//s^(2) ]

An harmonic wave has been set up on a very long string which travels along the length of the string. The wave has a frequency of 50 Hz, amplitude 1 cm and wavelength 0.5 m. find (a) the time taken by the wave to travel a distance of 8 m along the length of string (b) the time taken by a point on the string to travel a distance of 8 m, once the wave has reached the point and sets it into motion (c ) also. consider the above case when the amplitude gets doubled

Calculate the tension in the string shown in the figure. All the surfaces are frictionless. (Take g = 10// ms^(-1) )

The speed of a wave in a streched string is 20ms^(-1) and its frequency is 50 Hz. Calculate the phase difference in radian between two points situated at a distance of 10 cm on the string.

A 4.0 kg block is suspended from the ceiling of an elevator through a string having a linear mass desity of 19.2xx10^-3 kgm^-1 . Find the speed (with respect to the string) with which a wave pulse can proceed on the string if the elavator accelerates up at the rate of 2.0ms^-2. Take g=10 ms^-2 .

A harmonic wave has been set up on a very long string which travels along the length of string. The wave has frequency of 50 Hz. Amplitude 1 cm and wavelength 0.5 m. for the above described wave. Statement (i): time taken by a point on the string to travel a distance of 8 m along the length of string is 0.32 s. Statement (ii): time taken by a point in the string to travel a distance of 8m, once the wave has reached at that point and sets it into motion is 0.32 s.

A uniform string of length 20m is suspended from a rigid support. A short wave pulse is introduced at its lowest end. It starts moving up the string. The time taken to reach the support is : (take g = 10ms^(-2) )